36 lines
705 B
Python
36 lines
705 B
Python
#!/usr/bin/env python3
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'''
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Perform an HTTP request to a URL and exit with an exit code of 1 if the
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request did not return an HTTP/200 status code.
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Usage:
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$ ./healthcheck.py http://some.url.here/healthcheck/resource
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'''
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import sys
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import requests
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TIMEOUT = 5 # Seconds
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def do_heatlhcheck(url):
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headers = {'User-Agent': 'healthcheck'}
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response = requests.get(url, headers=headers, timeout=TIMEOUT)
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return response.status_code == 200
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if __name__ == '__main__':
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try:
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url = sys.argv[1]
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except IndexError:
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sys.stderr.write('URL must be supplied\n')
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sys.exit(1)
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if do_heatlhcheck(url):
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sys.exit(0)
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else:
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sys.exit(1)
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